y^2+18y-34=0

Solution for y^2+18y-34=0 equation:

y^2+18y-34=0

a = 1; b = 18; c = -34;
Δ = b2-4ac
Δ = 182-4·1·(-34)
Δ = 460
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{460}=\sqrt{4*115}=\sqrt{4}*\sqrt{115}=2\sqrt{115}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{115}}{2*1}=\frac{-18-2\sqrt{115}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{115}}{2*1}=\frac{-18+2\sqrt{115}}{2}
$